The function of ${ZnCl}_{2}$ in Lucas test for alcohols is

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To act as neutral catalyst

To act as base catalyst and react with $NaOH$ to form ${Na}_{2} Zn (OH)_{4}$

To act as amphoteric catalyst

To act as acid catalyst and react with $HCl$ to form $H_{2} {ZnCl}_{4}$

answer is A.

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Detailed Solution

Lucas test : In the presence of anhydrous ${ZnCl}_{2}$ alcohol reacts with cone. $HCl$ to produce alkyl chloride.

$ROH + HCl \overset{{ZnCl}_{2}}{⟶} RCl + H_{2} O$

Mechanism of Lucas test

$\begin{array}{l} 2 HCl + {ZnCl}_{2} ⟶ H_{2} {ZnCl}_{4} \\ ROH + H_{2} {ZnCl}_{4} ⟶ RCl + {ZnCl}_{2} + H_{2} O + HCl \\ __________________________________ \\ ROH + HCI \overset{{ZnCl}_{2}}{\to} RCI + H_{2} O . \\ ___________________________________ \end{array}$