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The function $(\sin^{2} ω t)$ represents

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A periodic but not simple harmonic motion

A simple harmonic motion with a period $\frac{2 π}{ω}$

A simple harmonic motion with a period half that of $\cos ω t$

A simple harmonic motion with a period twice that of $\cos ω t$

answer is C.

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Detailed Solution

$\sin^{2} ωt = \frac{1 - \cos 2 ωt}{2}$ .

So the particle will oscillate with a time period of $\frac{π}{ω}$ which is half of the time period of the shm $x = A \cos ω t$

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