The function f:A→B defined by f(x)=4x+7,x∈R is

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The function $f : A \to B$ defined by $f (x) = 4 x + 7, x \in R$ is

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odd

even

one-one

many-one

answer is A.

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Detailed Solution

We have, $f (x) = 4 x + 7, x \in R$

Let $x_{1}, x_{2} \in R$ , such that $f (x_{1}) = f (x_{2})$

$\begin{array}{l} \Rightarrow 4 x_{1} + 7 = 4 x_{2} + 7 \Rightarrow 4 x_{1} = 4 x_{2} \\ \Rightarrow x_{1} = x_{2} \end{array}$

So, f is one-one.

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