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Q.

The fundamental frequency of vibration of 1 m long string is 256 Hz. If the length of the string is reduced to 1/4 m keeping the tension unaltered, the new fundamental frequency will be

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a

256 Hz

b

512 Hz

c

1024 Hz

d

2048 Hz

answer is C.

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Detailed Solution

We know that, $n \propto \frac{1}{l}$

$∴ \frac{n_{2}}{n_{1}} = \frac{l_{1}}{l_{2}} \Rightarrow n_{2} = \frac{l_{1}}{l_{2}} \times n_{1}$

$= \frac{1 \times 256}{1 / 4} = 1024 Hz$

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