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Q.

The F—Xe—F bond angle in XeF4 is

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a

109°

b

103°

c

90°

d

60°

answer is C.

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Detailed Solution

In XeF4 the F—Xe—F bond angle is 90°. The Xe atom lies in the middle of the  XeF4 molecule, while the fluorine atoms are pointed in the direction of the square's four corners. It has a square pyramidal shape.

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