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The galvanometer shown in the figure has resistance $10 Ω$ . It is shunted by a series combination of a resistance $S = 1 Ω$ and an ideal cell of emf 2V. A current 2A passes as shown.

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The reading of the galvanometer is 1A

The reading of the galvanometer is zero

The potential difference across the resistance S is 1.5 V

The potential difference across the resistance S is 2 V

answer is B, D.

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Detailed Solution

LET X BE THE CURRENT THROUGH ‘S’

$2 - x = 10 (2 - x) \Rightarrow x = 2A$

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