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The gas liberated at electrode in dry cell is removed in the form a complex.The formula of the complex formed is

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${[Zn {({NH}_{3})}_{4}]}^{+ 2}$

${[Zn {({NH}_{3})}_{2}]}^{+ 2}$

${[Zn {({NH}_{3})}_{2}]}^{+ 4}$

${[Zn {({NH}_{3})}_{4}]}^{+ 1}$

answer is B.

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Detailed Solution

Gas liberated at anode is NH₃, and is removed in the form a complex with Zn⁺²

formed at anode as follows

${Zn}^{+ 2} + 4 {NH}_{3} \to {[Zn {({NH}_{3})}_{4}]}^{+ 2}$

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