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Q.

The gas liberated by treating diethylether with ${PCl}_{5}$ is

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a

$C_{2} H_{4}$

b

$C_{2} H_{5} COCl$

c

${CH}_{4}$

d

$C_{2} H_{5} Cl$

answer is C.

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Detailed Solution

Diethyl ether reacts with Phosphorous pentachloride on heating to form ethyl chloride.

$C_{2} H_{5} {OC}_{2} H_{5} + {PCl}_{5} \to 2 C_{2} H_{5} Cl + {POCl}_{3}$

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The gas liberated by treating diethylether with PCl5 is