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Q.

The gaseous compound NOBr decomposes according to the equation

NOBr(g)⇌NO(g)+12Br2(g)

At 350 K, the equilibrium constant, Kp is 0.15. What is the value of ΔG∘ ?

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a

2.4×103J/mol

b

−2.4×103J/mol

c

−5.5×103J/mol

d

5.5×103J/mol

answer is D.

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Detailed Solution

Gibbs free energy is given by,

ΔG∘=−RT ln ⁡KP

After putting the given values, we get,

ΔG∘=+5.5×103J/mol


 

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