Q.

The gaseous reaction A(g)2B(g)+C(g) is found to be first order. If the reaction is started with pA= 90 mmHg , the total pressure after 10 min is found to be 180 mmHg. The rate constant of the reaction is

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a

2.30×103s1

b

1.15×103s1

c

3.45×103s1

d

4.60×103s1

answer is A.

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Detailed Solution

A(g)p0-p2B(g2p)+C(g)p

Total pressure =p0p+(2p)+p=p0+2p

180mmHg=90mmHg+2p or       p=45mmHg

Now, logp0pp0=k2.303t

log4590=k2,303(10×60s). Thus   k=0.301×2.30310×60s=1.155×103s1

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