The general solution of sin2θsecθ+3tanθ=0 is

θ = n π + ( − 1 ) n + 1 π 3 , n ∈ Z

θ = n π + ( − 1 ) n + 1 π 3 , n ∈ Z

θ = n π + ( − 1 ) n + 1 π 6 , n ∈ Z

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The general solution of $\sin^{2} θ \sec θ + \sqrt{3} \tan θ = 0$ is

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$θ = \frac{n π}{2}, n \in Z$

$θ = n π + {(- 1)}^{n + 1} \frac{π}{3}, n \in Z$

$θ = n π, n \in Z$

$θ = n π + {(- 1)}^{n + 1} \frac{π}{6}, n \in Z$

answer is B.

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$\sin^{2} θ \sec θ + \sqrt{3} \tan θ = 0$

$\frac{\sin^{2} θ + \sqrt{3} \sin θ}{\cos θ} = 0$

$\sin θ = 0$

$\sin θ = - \sqrt{3}$

$θ = n π, n \in Z$

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