The general solution of the different equation dydx=1+x+y+xy is

dydx=(1+x)+y(1+x)dydx=(1+x)(1+y)

The general solution of the different equation dydx=1+x+y+xy is

dydx=(1+x)+y(1+x)dydx=(1+x)(1+y)

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The general solution of the different equation $\frac{d y}{d x} = 1 + x + y + x y$ is

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$\log (1 + x) = y + x^{2} / 2 + k$

$y = x + x^{2} / 2 + k$

$\log (1 + y) = x^{3} / 3 + k$

$y = k e^{x + x^{2} / 2} - 1$

answer is D.

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$\frac{d y}{d x} = (1 + x) + y (1 + x)$

$\frac{d y}{d x} = (1 + x) (1 + y)$

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The general solution of the different equation dydx=1+x+y+xy is

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The general solution of the different equation $\frac{d y}{d x} = 1 + x + y + x y$ is