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Q.

The general solution of the differential equation x(y2.exy+exy)dy=y(exyy2.exy)dx is

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a

exy+exy=c

b

exy=eyx+c

c

exy=exy+c

d

exy+eyx=c

answer is A.

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Detailed Solution

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x(y2.exy+exy)dy=y(exyy2.exy)dxy2(xdy+ydx)exy=exy(ydxxdy)exyd(xy)=ex/yydxxdyy2=exy.d(xy)exy=exy+c

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