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Q.

The general solution of tan3x=1 is

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a

nπ3+π12

b

nπ

c

nπ+π4

d

nπ±π4

answer is B.

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Detailed Solution

We have 

tan3x=1 tan3x=tanπ4 3x=nπ+π4x=nπ3+π12,nZ

 

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