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The geometric mean of 10 observations on a certain variable was calculated as 16.2. It was later discovered that one of the observations was wrongly recorded as 12.9; infact it was 21.9. The correct geometric mean is

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${(\frac{(16 .2)^{9} \times 21 .9}{12 .9})}^{1 / 10}$

${(\frac{(16 .2)^{11} \times 21 .9}{12 .9})}^{1 / 11}$

${(\frac{(16 .2)^{10} \times 21 .9}{12 .9})}^{1 / 10}$

${(\frac{(16 .2)^{10} \times 12 .9}{21 .9})}^{1 / 10}$

answer is B.

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Detailed Solution

$G . M = \sqrt[10]{\frac{(16 .2)^{10} \times 21 .9}{12 .9}}$

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