The geometry and magnetic behavior of the complex [Ni(CO)₄] are

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Square planar geometry and diamagnetic

Tetrahedral geometry and diamagnetic

Square planar geometry and paramagnetic

Tetrahedral geometry and paramagnetic

answer is B.

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Detailed Solution

In Ni(CO)₄ Ni is in the zero oxidation state, i.e., it has a configuration of 3d⁸4s².
Since CO is a strong field ligand, it causes the pairing of unpaired 3d electrons.
Also, it causes the 4s electrons to shift to the 3d orbital, thereby giving rise to sp³hybridization and,
hence, tetrahedral shape. Since no unpaired electrons are present in this case, [Ni(CO)₄] is
diamagnetic

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