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Q.

The geometry and magnetic behavior of the complex [Ni(CO)4] are

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a

Tetrahedral geometry and diamagnetic

b

Square planar geometry and diamagnetic

c

Square planar geometry and paramagnetic

d

Tetrahedral geometry and paramagnetic

answer is B.

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Detailed Solution

In Ni(CO)4 Ni is in the zero oxidation state, i.e., it has a configuration of 3d84s2.
Since CO is a strong field ligand, it causes the pairing of unpaired 3d electrons.
Also, it causes the 4s electrons to shift to the 3d orbital, thereby giving rise to sp3 hybridization and,
hence, tetrahedral shape. Since no unpaired electrons are present in this case, [Ni(CO)4] is
diamagnetic

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