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The given circuit shows two capacitors connected to a battery. After the capacitors are completely charged. The battery is removed and the capacitors are connected with plates of opposite polarity together. Then the charge on 2C and the energy lost in the process are respectively

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$0, \frac{2 C E^{2}}{3}$

$0, \frac{C E^{2}}{3}$

$Q, \frac{2 C E^{2}}{3}$

$2 Q, \frac{C E^{2}}{3}$

answer is B.

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Detailed Solution

Total capacitance before removing the battery $= \frac{2 C}{3}$
Initial energy $= \frac{1}{2} (\frac{2 C}{3}) E^{2}$
If opposite polarit plates are connected charge on each capacitor is zero

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