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The given diagram indicated the energy levels of a certain atom. When the system moves from 2E level to E level, a photon of wavelength $λ$ is emitted. The wavelength of the photon emitted during its transition from 4E/3 level to E level is

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$\frac{λ}{3}$

$\frac{3 λ}{4}$

$\frac{4 λ}{3}$

$3 λ$

answer is D.

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Detailed Solution

$2 E - E = \frac{h c}{λ}$

$\frac{4 E}{3} - E = \frac{h c}{λ'}$

Dividing, $\frac{E}{E / 3} = \frac{λ'}{λ} \Rightarrow λ' = 3 λ$

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