The given diagram represents a screw gauge. The circular scale is divided into 50 divisions and the linear scale is divided into millimeters. If the screw advances by 1 mm when the circular scale makes 2 complete revolutions, the reading of the instrument in the figure is ____mm

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Detailed Solution

$\begin{array}{l} Pitch of the screw = \frac{1 m m}{2} = 0.5 m m \\ Least count = \frac{0.5}{50} = 0.01 m m \\ ∴ Reading = Linear scale reading + (coinciding circular scale \times least count) \\ = 3.0 + (32 \times 0.01) \\ = 3.0 + 0.32 \\ = 3.32 m m \end{array}$

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