The given fig. represents P-V diagram for Carnot's reversible cycle. The correct representation of T-S diagram for the cycle will be:
 

$dS=\frac{dQ}{T}$

Along AB: heat is given to the system, hence entropy will increase.

Along BC: adiabatic process, entropy will remains the same.

Along CD: heat is removed from the system, entropy will decrease.

Along DA: adiabatic process, entropy will remains the same.