The given figure depicts a solid composed of a solid cube with a side of $40 \mathrm{cm}$and a solid cylinder with a radius of $20 \mathrm{cm}$and a height of $50 \mathrm{cm}$ attached to the cube. Calculate the volume and total surface area of the entire solid. (Use pi = 3.14)

Given: 

Side of the cube $=40 \mathrm{cm}$ and,

Radius of the cylinder $=20 \mathrm{cm}$ and, 

Height of the cylinder $=50 \mathrm{cm}$

Volume of cube $=(\text{ side }{)}^3$

$={\left(40\right)}^3$

$=64000 {\text{cm}}^3$

Volume of cylinder $=\pi r^{2}h$

$=3.14\times {\left(20\right)}^2\times 50=62800 {\text{cm}}^3$

So, total volume of solid $=64000+62800=126800{ \mathrm{cm}}^3$

Now, surface area of cube $=6(\text{ side }{)}^2$

$=6{\left(40\right)}^2=9600 {\text{cm}}^2$

The surface area of cylinder

 $=2\pi \mathrm{rh}=50 \mathrm{cm}$

$=3.14\times 20\times 50=6280 {\text{cm}}^2$

 Total surface area of solid $=9600+6280=15880{ \mathrm{cm}}^2$