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The given figure represents two isobaric processes for the same mass of an ideal gas, then

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$P_{1} = P_{2}$

$P_{2} \geq P_{1}$

$P_{1} > P_{2}$

$P_{2} > P_{1}$

answer is D.

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Detailed Solution

$P V = n R T \Rightarrow V = (\frac{n R}{P}) T S l o p e = \frac{n R}{P} S l o p e α \frac{1}{P} {(S l o p e)}_{2} > {(S l o p e)}_{1} \Rightarrow P_{2} < P_{1}$

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