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Q.

The given figure shows a disc on which a player spins an arrow twice. The fraction x y  is formed, where a   is the number of sectors on which the arrow stops on the first spin and b   is the number of the sectors in which the arrow stops on the second spin. In each spin, each sector has equal chance of selection by the arrow, then the probability that the fraction a b >1  .


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a

5 4  

b

5 12  

c

5 6  

d

1 12   

answer is B.

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Detailed Solution

Given, the given figure shows a disc on which a player spins an arrow twice. The fraction x y  is formed, where a   is the number of sectors on which the arrow stops on the first spin and b   is the number of the sectors in which the arrow stops on the second spin. In each spin, each sector has an equal chance of selection by the arrow.
An inequality is a connection that makes a non-equivalent correlation between two numbers or other numerical articulations.
Question Image There are 6 divisions, hence the possible outcomes will be 6.
So, the outcomes are 1,2,3,4,5 and 6 so for a and b, each will have 6 possible outcomes.
Hence, the total number of outcomes is 6×6=36  
The outcomes are given as:
a123456   1 1 1 2 1 3 1 4 1 5 1 6 1  
  2 1 2 2 2 3 2 4 2 5 2 6 2  
  3 1 3 2 3 3 3 4 3 5 3 6 3   4 1 4 2 4 3 4 4 4 5 4 6 4  
  5 1 5 2 5 3 5 4 5 5 5 6 5   6 1 6 2 6 3 6 4 6 5 6 6 6   The outcomes can be stated as-
a b >1 are  2 1 , 3 1 , 4 1 , 5 1 , 6 1 , 3 2 , 4 2   5 2 , 6 2 , 4 3 , 5 3 , 6 3 , 5 4 , 6 4  and  6 5  .
The number of favourable outcomes are 15.
Hence, the probability is 15 36 = 5 12  
In each spin, each sector has an equal chance of selection by the arrow, then the probability that the fraction a b >1  is 5 12   .
Hence, option 2 is the correct answer.
 
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