The given graph displays the displacement versus time relationship for a disturbance travelling with a velocity of $1500 m / s$ . Calculate the wavelength of the disturbance.

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2 \times 1 0^{- 3} m

4 \times 1 0^{- 3} m

3 \times 1 0^{- 3} m

1.5 \times 1 0^{- 3} m

answer is C.

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Detailed Solution

The wavelength of the disturbance is

3 \times 1 0^{- 3} m

.
From the graph, the time period of the disturbance wave is,

T = 2 x 1 0^{- 6} s

And given that velocity of the disturbance,

v = 1500 m / s

We know,

v = \frac{λ}{T}

\Rightarrow λ = v \times T

\Rightarrow λ = 1500 m / s \times 2 \times 1 0^{- 6} s

\Rightarrow λ = 3000 \times 1 0^{- 6} m

∴ Wavelength of the disturbance

= 3 \times 1 0^{- 3} m

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