The given table represents the heights (in cm) of 50 students in a class. Find the median height of the class.

Height (in cm)	No. Of students
156	8
154	4
155	10
151	6
157	7
152	3
153	12

From the dataset, let us first calculate the cumulative frequency of data and find the total number of terms.

We observe that the number of terms n = 50 (even)

Applying the formula of the median for an even number of terms:

So, Median =

$\frac{{\mathbf{\left(}{\displaystyle \frac{n}{2}}\mathbf{\right)}}^{\mathbf{th}}\mathbf{ }\mathbf{term}\mathbf{ }\mathbf{+}\mathbf{ }{\mathbf{(}{\displaystyle \frac{n}{2}}\mathbf{ }\mathbf{+}\mathbf{ }\mathbf{1}\mathbf{)}}^{\mathbf{th}}\mathbf{ }\mathbf{term}}{\mathbf{2}}$

= $\frac{{\left({\displaystyle \frac{50}{2}}\right)}^{\mathrm{th}} \mathrm{term} + {({\displaystyle \frac{50}{2}} + 1)}^{\mathrm{th}} \mathrm{term}}{2}$

= $\frac{{25}^{\mathrm{th}} \mathrm{term} + {26}^{\mathrm{th}} \mathrm{term}}{2}$

For the 26^th term, we will take the value for the next greatest term after 25. i.e. 35^th term.

Thus, we will take 155 for the value of the 26^th term.

= $\frac{154 + 155}{2}$

= $\frac{309}{2}$

= 154.5

Therefore, the median is 154.5 cm.