The good method for converting benzene into propyl benzene is:

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$C_{6} H_{6} + {CH}_{3} {CH}_{2} {CH}_{2} Cl + Anhyd. {AlCl}_{3}$

$C_{6} H_{6} + {CH}_{3} {CH}_{2} COCl + Anhyd. {AlCl}_{3}$ and then treatment with $Zn / Hg / HCl$

$C_{6} H_{6} + {CH}_{3} {CH}_{2} COCl + Anhyd. {AlCl}_{3}$ and then treatment with $H_{2} Ni$

$C_{6} H_{6} + Anhyd. {AlCl}_{3} + Cyclopropane$

answer is B, D.

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Detailed Solution

In the second alternative, a -R group can attach to the benzene ring and form a stable carbocation, giving us a ketone attached to the ring. The ketone is then reduced by the reagents Zn, Hg, and HCl to give us a hydrocarbon, and as a result, propyl benzene. The reaction can be expressed as: