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Q.

The graph between the resistive force F acting on a body and the distance covered by the body is shown in the figure. The mass of the body is 25 kg and initial velocity is 2 m/s. When the distance covered by the body is 4 m, its kinetic energy would be:

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a

50 J

b

40 J

c

10 J

d

20 J

answer is C.

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Detailed Solution

Initial KE of the body $= \frac{1}{2} {mv}^{2} = \frac{1}{2} \times 25 \times 4 = 50 J$

Work done against resistive force = Area between F-x graph

$= \frac{1}{2} \times 3 \times 20 = 30 J$

Final KE = Initial KE – Work done against resistive force

= 50 - 30 =20 J

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The graph between the resistive force F acting on a body and the distance covered by the body is shown in the figure. The mass of the body is 25 kg and initial velocity is 2 m/s. When the distance covered by the body is 4 m, its kinetic energy would be: