Q.

The graph obtained between ln k (k= Rate constant) on y-axis and 1/T on x-axis is a straight line. The slope of it is -4 x104 k. The activation energy of the reaction  (in kJmol1 ) is R=8.3JK1mol1

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a

166

b

332

c

382

d

765

answer is B.

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Detailed Solution

According to the Arrhenius equation:

ln k=-EaRT+ln A EaR=4×104 Ea8.3=4×104 Ea=33.2×104 J/mol=33.2×104×10-3=332 kJ/mol

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