The graph of alternating emf versus time is shown in the figure. The average of this alternating emf in the first one-half cycle will be

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$5 V_{0} / 8$

$V_{0} / 2$

$V_{0} / \sqrt{3}$

$4 V_{0} / 5$

answer is B.

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Detailed Solution

$V_{avg} = \frac{\int_{0}^{T / 2} Vdt}{\int_{T / 2} dt} .$ Area of the triangle divided by the time interval (T/2) will also provide the
average value of the signal.

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