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Q.

The graph of current versus time in a wire is given by
If charge that flows through a wire in 7.5 s is $q_{1}$ and that flows through the wire in 15s is $q_{2}$ , then ratio $q_{1} : q_{2}$ is

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a

1 : 4

b

2 : 1

c

1 : 2

d

4 : 1

answer is D.

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Detailed Solution

We know $i = \frac{d q}{d t}$

$\Rightarrow q = \int i d t$

Which is area under the curve for i-t curve.

$∴ \frac{q}{q_{2}} = \frac{1 / 2 \times 6 \times 7.5}{15 \times 6} = \frac{1}{4}$

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