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The graph of $y = x^{2} - 4 x + 4$

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touches the X-axis and lies entirely below the X-axis

lies entirely below the X-axis

touches the X-axis and lies entirely above the X-axis

lies entirely above the X-axis

answer is C.

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Detailed Solution

$y = x^{2} - 4 x + 4$

$a > 0, Δ = b^{2} - 4 a c$

$= 4 - 4 = 0$

So the graph touches x-axis and lies entirely above x-axis

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