The graph shown in figure is exponential. Write down the equation corresponding to the graph.

$y=-4+8e^{-Kx}.\text{ Here, }K\text{ is a positive constant }$

$y=4-8e^{-Kx}.\text{ Here, }K\text{ is a positive constant }$

$y=4+8e^{-Kx}.\text{ Here, }K\text{ is a positive constant }$

$y=-4-8e^{-Kx}.\text{ Here, }K\text{ is a positive constant }$