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The graph shows how the inverse of magnification $\frac{1}{m}$ produced by a thin convex lens varies with object distance u. What was the focal length of the lens used?

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$\frac{b}{c}$

$\frac{b}{ca}$

$\frac{bc}{a}$

$\frac{c}{b}$

answer is D.

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Detailed Solution

$\begin{array}{l} \frac{1}{v} - \frac{1}{(- u)} = \frac{1}{f} \Rightarrow \frac{1}{m} = \frac{u}{f} - 1 \\ ∴ \frac{1}{f} = \frac{b}{c} \Rightarrow f = \frac{c}{b} \end{array}$

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