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The graph shows the observed intensity of X – rays produced from two Coolidge tubes A, and B as a function of wavelength $λ$ . For tube A, the potential difference between the filament and target is $V_{A}$ and atomic number of target is $Z_{A} .$ For tube B the corresponding potential difference is $V_{A}$ and atomic number is $Z_{B} .$ Then

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$Z_{A} < Z_{B}; V_{A} < V_{B}$

$Z_{A} < Z_{B}; V_{A} > V_{B}$

$Z_{A} > Z_{B}; V_{A} > V_{B}$

$Z_{A} > Z_{B}; V_{A} < V_{B}$

answer is B.

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Detailed Solution

$λ_{\min} α \frac{1}{V} a n d \sqrt{\frac{C}{λ}} = a (Z - b)$

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