Q.

The graph shows the variation of displacement of a particle executing S.H.M. with time. We infer from this graph that

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a

The P.E. is equal to total energy at time T/2

b

The force is zero at time 3T/4

c

The velocity is maximum at time T/2

d

The acceleration is maximum at time T

answer is D.

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Detailed Solution

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At time T2;v=0, KE=0

Total energy = Potential energy.

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