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The graph shows the variation of displacement of a particle executing S.H.M. with time. We infer from this graph that

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The P.E. is equal to total energy at time $T / 2$

The force is zero at time $3 T / 4$

The velocity is maximum at time $T / 2$

The acceleration is maximum at time T

answer is D.

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Detailed Solution

At time $\frac{T}{2}; v = 0$ , KE=0

Total energy = Potential energy.

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