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The gravitational field intensity at a point 10,000 km from the centre of the earth is 4.8 N ${kg}^{- 1}$ . The gravitational potential at that point is

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$- 4.8 \times 10^{- 7} J {kg}^{- 1}$

$- 2.4 \times 10^{7} J k^{- 1}$

$4.8 \times 10^{6} J {kg}^{- 1}$

$3.6 \times 10^{6} J {kg}^{- 1}$

answer is A.

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Detailed Solution

Gravitational field intensity, $E = \frac{GM}{R^{2}}$

Gravitational potential, $V = - \frac{GM}{R}$

$∴ \frac{V}{E} = - R$

or $V = - ER = - 4.8 \times 10, 000 \times 10^{3}$

= $- 4.8 \times 10^{7} J {kg}^{- 1}$

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