Q.

The gravitational force acting on a particle due to a solid sphere uniform density and radius R, at a distance of 3R from the center of the sphere id  F1. A spherical hole of radius R2  is now made in the sphere as shown. The sphere with hole now exerts a force  F2 on the same particle. Ratio of F1  and F2 is
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a

4150

b

4142

c

2541

d

5041

answer is A.

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Detailed Solution

F1=GMm3R2=GMm9R2
F2=GMm9R2=GM8m5R22=GMmR21948×25
F1F2=5041

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