The gravitational potential energy of a rocket of mass 100 kg at a distance 107 m from the earth's mass is 4.8 x 109 joule. The weight of the rocket in newton at a distance 109m is

U=GMmRr or GM=Urm……………….(1)weight at a distance r=mg=mGMR2……………………(2)∴ W=m1R2⋅Urm=UrR2=4×109(10)71092=4×10−2

The gravitational potential energy of a rocket of mass 100 kg at a distance 107 m from the earth's mass is 4.8 x 109 joule. The weight of the rocket in newton at a distance 109m is

U=GMmRr or GM=Urm……………….(1)weight at a distance r=mg=mGMR2……………………(2)∴ W=m1R2⋅Urm=UrR2=4×109(10)71092=4×10−2

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

The gravitational potential energy of a rocket of mass 100 kg at a distance 10⁷ m from the earth's mass is 4.8 x 10⁹ joule. The weight of the rocket in newton at a distance 10⁹m is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$8 \times 10^{- 3}$

$8 \times 10^{- 2}$

$4 \times 10^{- 3}$

$4 \times 10^{- 2}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$U = \frac{GMm}{Rr} or GM = \frac{Ur}{m}$ ……………….(1)
weight at a distance r
$= mg = m \frac{GM}{R^{2}}$ ……………………(2)
$\begin{aligned} ∴ W = m \frac{1}{R^{2}} \cdot \frac{Ur}{m} = \frac{Ur}{R^{2}} \\ = \frac{(4 \times 10^{9}) (10)^{7}}{{(10^{9})}^{2}} = 4 \times 10^{- 2} \end{aligned}$