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The greatest and least resultant of two forces are 7 N and 3 N respectively. If each of the force is increased by 3N and applied at 60°. The magnitude of the resultant is

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7 N

3 N

10 N

$\sqrt{129}$ N

answer is D.

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Detailed Solution

P + Q = 7N
P – Q = 3N

∴2P = 10N
P = 5N, Q = 2N

P¹ = 8N, Q¹ = 5N, $θ$ = 60^o
$\begin{array}{l} R^{1} = \sqrt{(8)^{2} + (5)^{2} + 2 \times 8 \times 5 \times \frac{1}{2}} \\ = \sqrt{64 + 25 + 40} = \sqrt{129} N \end{array}$

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