The greatest negative integer satisfying x2–4x–77 4 is

(x−11)(x+7) 0⇒x∈(−∞,−2)∪(2,∞)

The greatest negative integer satisfying x2–4x–77 4 is

(x−11)(x+7) 0⇒x∈(−∞,−2)∪(2,∞)

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The greatest negative integer satisfying x²–4x–77 < 0 and x² > 4 is

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–3

–2

–1

–7

answer is B.

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Detailed Solution

$(x - 11) (x + 7) < 0 \Rightarrow x \in (- 7, 11)$

$x^{2} - 4 > 0 \Rightarrow x \in (- \infty, - 2) \cup (2, \infty)$

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