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Q.

The greatest value of sin3x+cos3x in  [0,π2]  is

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a

1

b

2

c

3

d

4

answer is A.

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Detailed Solution

f(x)=sin3x+cos3xf1(x)=3sin2xcosx3cos2xsinx=0

sinx=cosxsinx=0,cosx=0

x=0,x=π2,x=π4

Max=max{f(0),f(π2),f(π4)} =max1,1,12      =1

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The greatest value of sin3⁡x+cos3⁡x in  [0,π2]  is