The greatest weight which can be contained exactly in 3kg 7hg 8dag 1g and 9kg 1hg 5dag 4g is:

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1hg 9dag 9g

1hg 8dag 9g

2hg 8dag 8g

2hg 9dag 9g

answer is A.

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Detailed Solution

Concept: By dividing each weight into prime factors, we can modify the given weights in a single unit before calculating their HCF. Additionally, the HCF of the weights will be products of common prime factors.
Knowing this,
1 kilogramme equals 1000 g.
1 hg = 100 g
1 dag = 10 g
Let's adjust the specified weights in grammar now (g).
Therefore, 3kg 7hg 8dag 1g =
Also, 9kg 1hg 5dag 4g will be =

Therefore, we had to determine the maximum weight that could be precisely contained in 3781 g and 9154 g. And the HCF of 3781 and 9154 will be the most weight that can be contained. The HCF will be the product of those factors that are common to both numbers, and in order to calculate the HCF of two numbers, we had to divide them into the product of prime factors. Consequently, dividing both numbers as the prime factor product.

Therefore, the HCF of 3781 and 9154 will equal 199, making 199 the common factor between the two numbers. Therefore, 199g will be the maximum weight that can be precisely contained in 3 kg, 7 kg, 8 kg, and 9 kg, 1 kg, 5 kg. Now changing 199 grams into hg,
100 grams = 1hg
10 grams = 1deg

Hence, option 1 is the correct answer.

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