The green color produced in the Borax bead test of a Chromium(III) salt is due to

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${Cr}_{2} {(B_{4} O_{7})}_{3}$

$Cr {({BO}_{2})}_{3}$

CrB

${Cr}_{2} O_{3}$

answer is C.

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Detailed Solution

${Na}_{2} B_{4} O_{7} . 10 H_{2} O \overset{Δ}{\to} {Na}_{2} B_{4} O_{7} \overset{Δ}{\to} {Na}_{2} {NO}_{2} + B_{2} O_{3} {Cr}_{2} O_{3} + 3 B_{2} O_{3} \to 2 Cr {({BO}_{2})}_{3} Chromium meta borate .$

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