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The ground state energy of H-atom is -13.6ev. The energy of second excited state of $H e^{+}$ ion in ev is

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-54.4

-6.04

-3.4

-27.2

answer is C.

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Detailed Solution

$E = - 13.6 \times \frac{z^{2}}{n^{2}} = - 13.6 \times \frac{4}{9} = - 6.04 e v$

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