The H-Cl bond length is 1.275 $\stackrel{\mathrm{o}}{\mathrm{A}}$ (charge e - 4.8 × 10^-10 esu). lf $\mu$ = 1.02 D, then HCI is

The percent ionic nature

$=\frac{\text{ Observed }\mu }{\text{ Theoretical }\mu }\times 100=\frac{1.02}{1.275\times 4.8}\times 100$

= l7 % ionic or = 83% covalent.