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The $H - M - H$ bond angle of 15 group hydrides decrease from $107 ° to 90 °$ from NH₃, to ${SbH}_{3}$ ; this is due to:

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increase in basic strength with molecular weight

use of pure p-orbital for $M - H$ bonding in hydrides of higher molecular weight

bond energies of M-H bonds increase

bond pairs of electrons go closer to central atom

answer is B.

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use of pure p-orbital for $M - H$ bonding in hydrides of higher molecular weight

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