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Q.

The half-equation for the reduction of perbromate ion is BrO4-+8H++7e-12Br2+4H2O. How many moles of bromine are produced when 965 A of current is passed for 1400 sec through perbromate ion is 

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a

0.1

b

1

c

0.05

d

0.5

answer is B.

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Detailed Solution

Number of coulombs = 965 ×1400

Moles of bromine liberated = 14×0.57=1

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The half-equation for the reduction of perbromate ion is BrO4-+8H++7e-→12Br2+4H2O. How many moles of bromine are produced when 965 A of current is passed for 1400 sec through perbromate ion is