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Q.

The half-life for the reaction N2O5⇌2NO2+12O2 is  24 hr at 30oC. Starting with 10 g of N2O5 how many grams of N2O5 will remain after a period of 96 hours? 

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a

1.25 g

b

0.5 g

c

1.7 g

d

0.63 g

answer is B.

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Detailed Solution

k=0.69324hr−1=2.30396log⁡10a−x

 log⁡10a−x=1.2036

 1−log⁡(a−x)=1.2036

 log⁡(a−x)=−0.2036

 (a−x)=antilog -0.2036=0.6258 g

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