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The half life of a radioactive nucleus is 50 days. The time interval $(t_{2} - t_{1})$ between time $t_{2}$ when 2/3 of it has decayed and time $t_{1}$ when 1/3 of it had decayed is

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60 days

15 days

30 days

50 days

answer is D.

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Detailed Solution

$\frac{N}{N_{0}} = \frac{1}{2} t / T t_{2} - t_{1} = T = 50$

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