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Q.

The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be :

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a

2/3

b

232

c

1/2

d

122

answer is C.

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Detailed Solution

A=A02t/T1/2⇒AA0=2−t/T1/2=2−150100=2−3/2=122

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